X^2x+1=4(x+5)

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Solution for X^2x+1=4(x+5) equation:


Simplifying
X2x + 1 = 4(x + 5)

Reorder the terms:
1 + xX2 = 4(x + 5)

Reorder the terms:
1 + xX2 = 4(5 + x)
1 + xX2 = (5 * 4 + x * 4)
1 + xX2 = (20 + 4x)

Solving
1 + xX2 = 20 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
1 + -4x + xX2 = 20 + 4x + -4x

Combine like terms: 4x + -4x = 0
1 + -4x + xX2 = 20 + 0
1 + -4x + xX2 = 20

Add '-1' to each side of the equation.
1 + -4x + -1 + xX2 = 20 + -1

Reorder the terms:
1 + -1 + -4x + xX2 = 20 + -1

Combine like terms: 1 + -1 = 0
0 + -4x + xX2 = 20 + -1
-4x + xX2 = 20 + -1

Combine like terms: 20 + -1 = 19
-4x + xX2 = 19

Reorder the terms:
-19 + -4x + xX2 = 19 + -19

Combine like terms: 19 + -19 = 0
-19 + -4x + xX2 = 0

The solution to this equation could not be determined.

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